(4x^2-35x+51)(1/x+7)

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Solution for (4x^2-35x+51)(1/x+7) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(4*x^2-(35*x)+51)*(1/x+7) = 0

(4*x^2-35*x+51)*(1/x+7) = 0

(4*x^2-35*x+51)*(x^-1+7) = 0

4*x^2-35*x+51 = 0

4*x^2-35*x+51 = 0

DELTA = (-35)^2-(4*4*51)

DELTA = 409

DELTA > 0

x = (409^(1/2)+35)/(2*4) or x = (35-409^(1/2))/(2*4)

x = (409^(1/2)+35)/8 or x = (35-409^(1/2))/8

(x-((35-409^(1/2))/8))*(x-((409^(1/2)+35)/8)) = 0

(x-((35-409^(1/2))/8))*(x-((409^(1/2)+35)/8))*(x^-1+7) = 0

( x-((35-409^(1/2))/8) )

x-((35-409^(1/2))/8) = 0 // + (35-409^(1/2))/8

x = (35-409^(1/2))/8

( x-((409^(1/2)+35)/8) )

x-((409^(1/2)+35)/8) = 0 // + (409^(1/2)+35)/8

x = (409^(1/2)+35)/8

( x^-1+7 )

1*x^-1 = -7 // : 1

x^-1 = -7

-1 < 0

1/(x^1) = -7 // * x^1

1 = -7*x^1 // : -7

-1/7 = x^1

x = -1/7

x in { (35-409^(1/2))/8, (409^(1/2)+35)/8, -1/7 }

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